Amazing Analogies for Random Terms

October 20, 2011

Lots of people need random definitions for random things… yeah anyways…

So the response is marked as “Immortal Being” and the questioners will be “Mortal Being”

Finally, before we begin, this section is not only loaded with inside jokes, but also names that are chosen at completely random. As such only first names will be mentioned.

Mortal Being: What does it mean to be the most-favored nation (Jay’s Treaty context)?

Immortal Being: Obviously the definition is too complex for mortals to get, so a quick and easy way of explaining it through analogies. So there was this guy called Raymond. He was an old guy from Canadaand he managed to harvest 433 units of “Love” this fall. There were two people, Audrey and Emily who both needed the “Love” Raymond harvested. So under normal circumstances, Raymond would have tried to divide out his “Love” as evenly as possible. Hearing about this amazing harvest, Audrey and Emily both want 400 units. But, unfortunately (or I would say fortunately), Raymond had recently formed the most-favored nation bond with Audrey. Normally, both countries would recieve relatively equal ammounts of “Love”, but under most-favored nation bond, Raymond has to sell 400 units to Audrey, leaving Emily with only 33 units. Thus Emily is pissed and breaks contact with Raymond and go finds some other random guy who ccan sell her what she needs, and Audrey is happy and continues to ally with Raymond.


Daily Question #3

September 20, 2010

What in the world is… antiferromagnetism…?

Yeah… Raymond: 1


Daily Question #2

September 15, 2010

Yesterday there was no answer… so I’ll wait patiently for it.

Question 2:

What are Plyometrics?


Daily question #1

September 14, 2010

What are Federalists and Anti-federalists?

Just leave your answer in a comment.

Answers will be posted on the next daily, with a running total of the person who gets them first.

Oh and my answers will be as simple as they can get. But yours can be as complex as you want.


Areas

April 1, 2010

Rectangle=BH

Square=s^2

Parallelogram=BH

Triangle=1/2 BH

Trapezoid= 1/2 h(B1+B2) or M(h)

Kite=D1D2/2

Equilateral Triangle= S^2/4  Root3

Regular polygon=1/2 ap

Rhombus= base*h


Ch 10

March 22, 2010

10.1: The Circle

Circle- Set of all points in a plane that are equidistant from the center. A line from the center to any point on the circle is a radius.

2+ circles with the same center are cocentric.

Th. If a radius is perpendicular to a chord, it bisects that chord.

Th. If a radius bisects a non-diameter chord, it is perpendicular to it.

Th. The perpendicular Bisector of a chord passes thru the center of the chord

10.2 Congruent Chords

Th. If two chords are equidistant from the center, they are congruent.

Th. If two chords are congruent, they are equidistant.

10.3 Arcs

Minor= arc whose points are on or between the sides of a central angle.

Major- Arc whose points are on or outside of a central angle.

Th. If two central angles of a circle are congruent, than their intercepted arcs are too, and thus the corresponding chords are congruent.

Th. If two chords are congruent, than the corresponding arcs are too and thus so are the central angles.

10.4 Secants/Tangents

Tangent lines are perpendicular to the radius drawn to the point of contact.

If a line is perpendicular to a radius at its outer endpoint, then it is tangent to the circle.

Th. If two tangent lines are drawn from a single point than the lines are congruent.

10.5 Angles of a circle

If the point is inside of the circle it is half the sum of the intercepted arcs. If the point is on the circle, its just half the arc it intercepts. and if its outside the circle, it is half of the difference of the intercepted arcs.

10.6 more arc angle theorems

If two inscribed or tangent chord angles intercept congruent arc, they are congruent.

The sum of a tangent tangent angle and its minor arc is 180.

10.7

If a quad is inscribed in a circle, than opposite angles are supp.

10.8

If two chords of a circle intersect inside the circle, then the product of the measures of the segments of one chord is equal  to the product of the measures of the segments of the other chord.

If a tangent segment and a secant segment are drawn from an external point to the circle, then the square of the tangent segment is equal to the measures of the entire secant segment and its external part.

If two secant segments are drawn from an external point to a circle, than the product of the entire secant and its external part of one is equal to the product of the entire secant and its external part of the other.


ELECTIONS

March 10, 2010

Ok guys I totally love this.So some general postulates that I have to establish.

1. IT IS 100% A POPULARITY CONTEST. No doubt it is. The last proof of this will be James Ho losing to Allison Tong. James is not that popular, but he’s really pro at math and in real life would be a much better treasurer than Allison Tong (no offense meant, you would probably make a good treasurer too but I’m sure James would do much better) . However, Allison is about 100x if not 200x more popular (like seriously everyone knows her, and loves her and etc. and like only complete nerds or ceramics guys know James). So unfortunately, James will probably lose. What a pity old buddy.

2. Posters=waste of paper. Most people just post the same things over and over and over and over and over and over and over and over and… ok you get the point, again and other than a specific few (Mr. Wilson & some others), no one pays much attention to them. And of course, they vote for their friends. So if you have billions of friends, and your opponent doesn’t, then don’t bother with the posters. Just walk around and talk to people.

3. Facebook groups=let’s either join all of them or ignore all of them. Seriously guys, its kinda pointless. I join about every single group that I deem somewhat important. or heck sometimes i press confirm because my mouse is closer to the confirm button than it is to the ignore button. So yeah, seriously… those things are pointless except to be used to show more of your popular face in the crowd (which therefore means that you don’t need one as Postulate#1 makes certain of your victory).

4. The only time any of the previous (except #1) is proven false is when the people are equally popular. But we’ll go to that later… or sometime soon.

Theorems:

1. A good speech means you win.

Proof: Lucy Shen won her election by the masses because her speech was way better than her opponents.

2. If you don’t win, you didn’t have a good speech.

Proof: Doug Wilson didn’t win. He didn’t have a good speech.

3. Randomly Filing out a ballot wastes school paper.

Proof: Go ask Vikram for his opinion. Be sure to have protection though.

4. Multitask is what we can do.

Given: We’re playing cards, and you walk past and start talking.

Prove: We can still hear you.

S                                                  | R

1. Givens.                                 | Given

2. We can still hear you.      | Definition of Multitasking

Funnies:

Today, during lunch, a bunch of people walked by and were like VOTE FOR ME!
So Monica Liu, one of our candidates for Secretary came and she gave her random speech and then she was like vote for me! Tristan walks by and was like “psst… David don’t vote for her!”
Monica’s like “why?” and Elbert’s like because we vote for people with the biggest breast size. Monica asks him to repeat it, to which he follows the order and repeats it. Then he follows with “wait so whats yours?”

Moral: Never ask why people shouldn’t vote for you.

2nd Moral: Ignore the first moral. I makes people laugh and think your a cool person and vote for you.

Note: If you happen to make this list. I swear that you have my vote. So yeah. To win more votes, come get harassed by Kevin and Elbert.


UPDATE# (1+x): READ

March 3, 2010

where x = the last update number… if there was one.

Anyways, lots of stuff to discuss. So I think i might start.

Q. GO update your homework page.

A. … that’s not a question. But ok. As i have badminton practice now, and a whole bunch of stuff, i will momentary drop the homework updates until badminton season is over.

Q. You in varsity?

A. Nope… but i have a plan to get in… just wait.

Q. Will the math stuff still come up before 1 AM before the quiz/test?

A. yeah. They are easy to manage.

Q. Wheres’s Chapter 2?

A. The next part is difficult. And if japan can have a break from writing One Piece, i can have a break. It’ll be there after Spring Break.

Q. Any changes?

A. Totally. The sites going to totally change. Badminton stuff will be added. Homework Page will be retired momentarily. Etc… Just wait and see.

Q. … Uh…

A. stop asking questions… It’s not a QA session…

So yeah, there we go. Hope you guys don’t miss the hmwk thing too much. I wonder who can still remember the good 3 month period when i actually updated before 5 PM…

BTW. IF YOU ARE IN JV FOR BADMINTON. RECOMMEND DRILLS. TRUST ME.


Ch 9 (Supposed to be difficult. IF SO READ! XD)

February 22, 2010

Yeah the quiz was really gay. Lots of lateral thinking required, and lots of other stuff that you probably forgot. Review chapters to remember crap.

9.1 Radicals

Well I’m just going to do examples. You might want to know some notation before you read on though.

(200)^1/2=10(2)^1/2

5(18)^1/2=15(2)^1/2

1/(2)^1/2=(2)^1/2 /2

4(3)^1/2+7(3)^1/2=11(3)^1/2

x^2=25; x=5 or -5

x^2+16=25; x=3 or -3

9.2 Circles (the joy of a figure whose points are equidistant from the center…)

So first of all parts of a circle (as if you didn’t know this XD)

RADII=line from the center to any point on the circle

DIAMETER=line between any two points on a circle that crosses the center of the circle

CIRCUMFERENCE= the measure of the total length of the line that forms the circle (sorry this is a really baad definition but by golly, I’m not a professor)

ARC= part of a circumference

AREA= amount of room the circle occupies

Sector= part of the circle bounded by two radii

Chord= any random line that connects two points of a circle

So for arcs, to find the LENGTH, you find the DIAMETER, multiply that by Pi, and then multiply by the amount of the circumference that it takes up. Usually the give you some sort of degree to work with. Just remember its degree that they somehow manage to give you/360 degrees

Ex. Arc around a 90 degree thingy of a circle with a diameter of 4.

16Pi-> 4Pi= LENGTH

Measure= (degree that they somehow manage to give you/360 degrees) * 360

for the previous one, (90/360)*360=90 degrees

Area of sector is found by finding the area and then multiplying that by degree that they somehow manage to give you/360 degrees.

SUMMARY:  DONT FORGET (degree that they somehow manage to give you/360 degrees)

Part two of this lesson talks about inscribed angles of a circle. Just note that the inscribed angle is half the measure of its intercepted arc. That’s all you need for this chapter.

9.3 Alt-Hyp theorems (Or the stuff thats probably why people fainted on the quiz. lets just hope that I remember this when I take it)

So image triangle ABCD or heck ill draw points and you imagine the triangle

C

A         D                       B

There you can see the altitude right?… Anyways… The three triangles you see here are all similar…

AB/AC=AC/AD as such-> AB/CB=CB/DB

So from this it means that the ratio between the hyp of two triangles is equal to ratio between the same side (opp or adj) of the triangles.

And why not just say that if the ratio between the same side (opp, hyp, or adj) of two right triangles equal the ratio between the other side (opp, hyp, or adj) of the triangles

Therefore from the above triangle, we can do means-extremes and get something like AC^2=AB*AD and so on and so forth for the rest of the formulas.

Anyways the quick theorems to remember.

CD^2=AD*DB

CB^2=AB*DB

AC^2=AB*AD

BE SURE TO NOTE THAT this is only true if an altitude is drawn to the hypotenuse of a right triangle. But for the quiz purpose, screw formalities and just memorize the theorems.

9.4 Pyth Theorem (not to sound like a loser and a stuckup guy but did we not learn this in like 6th grade? Anyways…)

Anyways… in a triangle ABC where Side C is the Hypothenuse, the A^2+B^2=C^2.

From the converse, we can find that if:

a^2+b^2>c^2 then acute

a^2+b^2=c^2 then right

a^2+b^2<c^2 then obtuse

So as an easy reminder a^2+b^2 is the feather of Maat. If its acute than the heart (or biggest angle) is lightweight and the feather rises (thus C^2 is less than the feather). If its obtuse, than the heart (or biggest angle) is heavyweight and the feather sinks (thus C^2 is more than the feather). and if its equal they are equal weight and the dog like animal is cheated.

Anyways. Just remember the formulas again.

Finally 9.5: Distance Formula.

(Once again, another review)

Such a review that im only gonna do examples again.

Distance between (4,0) and (6,0)

{[(6-4)^2]+[(0-0)^2]}^1/2-> [(2^2)+(0^2)]^1/2-> (4+0)^1/2-> 4^1/2->2

#7. 36/8=AD

Bc is can be solved after Ac is solved.

Anyways, that is all for the quiz, ill update again in about a week for the test. So yeah wish me luck and so long an so forth.

Stuff to remember: Similar triangles, Radii, angle rules, Supplementary rules, etc.

9.6-7 Families

Just remember the 30, 60 90 and the 45, 45, 90 ones the rest, just hope you have a decent calculator.

30′s opposite side: x

60′s opposite side: x(3)^1/2

90′s opposite side: 2x

45′s opposite side: x

90′s opposite side: x(2)^1/2

9.8 Space crap.

REC. To find the diagonal its L^2+W^2+H^2

Square pyramid: Slant height is the perpendicular to a side of a base.

Arg. you know this stuff. Circles are 360 degrees btw.

9.9-10 Law of (Co)sines

Sines: A/sin a=B/sin b=C/sin c

Cosines: C^2=A^2+B^2-2AB (cos C)

And yeah… G2g now. bb.


Ch. 14 Part 1

February 3, 2010

14.1 Mapping

Image to Pre-image->Plug into before the equal sign in f(x)=x+b

Pre-image to Image-> Plug into after the equal sign in f(x)=x+b

one to one (CORRESPONDING): One X to One Y and Vice-Versa

Point Imaging (Aka putting points into a {X+(variable), Y+(variable)})

Isometries: Addition, NOT MULTIPLYCATION


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